lines 6-60 of file: xrst/theory/sqrt_forward.xrst

{xrst_begin sqrt_forward}

Square Root Function Forward Mode Theory
########################################

If :math:`F(x) = \sqrt{x}`

.. math::

   F(x) * F^{(1)} (x) - 0 * F (x)  = 1/2

and in the
:ref:`standard math function differential equation<forward_theory@Standard Math Functions@Differential Equation>` ,
:math:`A(x) = 0`,
:math:`B(x) = F(x)`,
and :math:`D(x) = 1/2`.
We use :math:`a`, :math:`b`, :math:`d`,
and :math:`z` to denote the
Taylor coefficients for
:math:`A [ X (t) ]`,
:math:`B [ X (t) ]`,
:math:`D [ X (t) ]`,
and :math:`F [ X(t) ]` respectively.
It now follows from the general
:ref:`forward_theory@Standard Math Functions@Taylor Coefficients Recursion Formula`
that for :math:`j = 0 , 1, \ldots`,

.. math::
   :nowrap:

   \begin{eqnarray}
   z^{(0)} & = & \sqrt { x^{(0)} }
   \\
   e^{(j)}
   & = & d^{(j)} + \sum_{k=0}^{j} a^{(j-k)} * z^{(k)}
   \\
   & = & \left\{ \begin{array}{ll}
      1/2 & {\rm if} \; j = 0 \\
      0   & {\rm otherwise}
   \end{array} \right.
   \\
   z^{(j+1)} & = & \frac{1}{j+1} \frac{1}{ b^{(0)} }
   \left(
      \sum_{k=1}^{j+1} k x^{(k)} e^{(j+1-k)}
      - \sum_{k=1}^j k z^{(k)}  b^{(j+1-k)}
   \right)
   \\
   & = & \frac{1}{j+1} \frac{1}{ z^{(0)} }
   \left(
      \frac{j+1}{2} x^{(j+1) }
      - \sum_{k=1}^j k z^{(k)} z^{(j+1-k)}
   \right)
   \end{eqnarray}

{xrst_end sqrt_forward}